![]() Strrtrim( s) removes the trailing spaces. Stritrim( s) removes the multiple internal spaces. Strtrim( s) removes the leading or trailing spaces. The four functions trim the strings by removing the spaces. Replace rank = subinstr(rank,"`x'", "".)īack to top strtrim() stritrim() strltrim() strrtrim() We want to remove all the spaces, (1T), (2T), (3T) and (RU). Here we have a dataset with a variable rank: If n is missing, all occurrences are replaced. Subinstr( s1, s2, s3, n) replaces the first n occurrences in s1 of s2 with s3. From there we can convert it to a date and time variable. gen clock = substr(time, 1, 19) generates a new variable clock with the first 19 characters of time. Let's say we have a dataset with a string variable time and we want to extract the date and time components to the seconds. Substr( s, n1, n2) extracts the substring of s from n1 for the length of n2. ” and space into four new variables substr1-substr4. split make, p("." " ") gen(substr) splits make by “. The generate() option allows one to change the prefix of the new variables to be generated. The parse() option allows one to specify the separator. Split splits string variables by separators into several components, and generates new string variables for each component taken out from the original string. gen position = strpos(make,".") creates the new variable position that gives us the position of “.” in make. ![]() When positions are not found they return 0. Strrpos( s1, s2) returns the position of s2 where last found in s1; Strpos( s1, s2) returns the position of s2 where first found in s1 UCLA: Statistical Consulting Group, How can I extract a portion of a string variable using regular expressions? | Stata FAQ * matches zero or more of the preceding expression matches at least one of the values in the bracket Ī-zA-Z matches any value of the letters, uppercase or lowercase 0-9, similarly, will match any numbers in the specified numeric range gen make2 = regexs(1) if regexm(make, "(+)(|)*(+)") takes out the car make, the first part from its make and model combination in make strings. Regexs( n) must appear after regexm( s,re) and returns the n th substring from what is previously matched by regexm( s,re). Cases with all numeric characters have been replaced by "marked". gen id2 = regexr(id, "", "marked") generates a new variable id2. Regexr( s1,re,s2) replaces the string s1 that matches the regular expression re with s2. Then if we want to drop cases with non-numeric characters, we can easily do that. If the matching is successful, it returns 1 otherwise it returns 0.įor instance, gen flag = regexm(id, "") marks observations that contain numeric characters. Regexm( s,re) performs matching on the string s by regular expression re. Turner, What are regular expressions and how can I use them in Stata? Read how Stata’s regular expressions work: If you are a registered author of this item, you may also want to check the "citations" tab in your RePEc Author Service profile, as there may be some citations waiting for confirmation.įor technical questions regarding this item, or to correct its authors, title, abstract, bibliographic or download information, contact: Christopher F Baum (email available below). If you know of missing items citing this one, you can help us creating those links by adding the relevant references in the same way as above, for each refering item. You can help adding them by using this form. We have no bibliographic references for this item. It also allows you to accept potential citations to this item that we are uncertain about. This allows to link your profile to this item. If you have authored this item and are not yet registered with RePEc, we encourage you to do it here. See general information about how to correct material in RePEc.įor technical questions regarding this item, or to correct its authors, title, abstract, bibliographic or download information, contact. ![]() ![]() When requesting a correction, please mention this item's handle: RePEc:boc:bocode:s458884. You can help correct errors and omissions. All material on this site has been provided by the respective publishers and authors. ![]()
0 Comments
Leave a Reply. |
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |